Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO.

Präsentation zum Thema: "Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO."—  Präsentation transkript:

1 Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 KaoliniteKln AL 2 Si 2 O 5 (OH) 4 PyrophyllitePrl AL 2 Si 4 O 10 (OH) 2 WaterW H 2 O Nur stabile Reaktionen

2 Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 Nur stabile Reaktionen

3 Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 alle Reaktionen

4 Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 alle Reaktionen

5 Al 2 SiO 5

6 T ?

7 Gesucht: für 4000 Bar und 10000 Bar: ∆ a G(Sillimanit) = ∆ a G(Kyanit) ∆ a G(Sillimanit) - ∆ a G(Kyanit) = 0

8 678.5 o C

9 678.5 K

10

11 SillimanitKyanite V 0 [J/Bar] 4.99004.4090 Sillimanit - Kyanite 0.581

12 SillimanitKyanite V 0 [J/Bar] 4.99004.4090 Sillimanit - Kyanite 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J

13 ≠

14

15 SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] 4.99004.4090 Sillimanit - Kyanite -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J SillimanitKyanite Sillimanit - Kyanite

16 SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] 4.99004.4090 Sillimanit - Kyanite -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J + 2324 + 5810 SillimanitKyanite Sillimanit - Kyanite

17 SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] 4.99004.4090 Sillimanit - Kyanite -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J + 2324 + 5810 SillimanitKyanite Sillimanit - Kyanite 892 -244 135 -831

18 SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] 4.99004.4090 Sillimanit - Kyanite -2388660 -2339238 -2289948 -2240847 -2191922 -2143153 -2092987 -2042207 -2389682 -2339004 -2288516 -2238279 -2188275 -2138464 -2087312 -2035566 1022 -234 -1432 -2568 -3647 -4689 -5675 -6641 0.581 = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J + 2324 + 5810 SillimanitKyanite Sillimanit - Kyanite 892 -244 135 -831 678.5 K 1014.0 K

19 -244 892

20 -244 892 600 700 K ∆ r G(Sil-Ky) f 1 = a·x 1 + b f 2 = a·x 2 + b P = 4000 Bar

21 -244 892 600 700 K ∆ r G(Sil-Ky) f 1 = a·x 1 + b f 2 = a·x 2 + b Nullpunkt (∆ r G = 0) : P = 4000 Bar

22 -244 892 600 700 K ∆ r G(Sil-Ky) f 1 = a·x 1 + b a = (∂∆ r G/∂T) P = -∆ r S P = 4000 Bar ∆ r S = 11.69 J/K·mol

23 -244 892 600 700 K ∆ r G(Sil-Ky) f 1 = a·x 1 + b a = (∂∆ r G/∂T) P = -∆ r S P = 4000 Bar ∆ r S = 11.69 J/K·mol

24 -831 135 1000 1100 K ∆ r G(Sil-Ky) f 1 = a·x 1 + b f 2 = a·x 2 + b Nullpunkt (∆ r G = 0) : P = 10000 Bar

25 678.5 K 1014.0 K

26 678.5 K 1014.0 K

27 678.5 K 1014.0 K Kyanit Sillimanit