Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 KaoliniteKln AL 2 Si 2 O 5 (OH) 4 PyrophyllitePrl AL 2 Si 4 O 10 (OH) 2 WaterW H 2 O Nur stabile Reaktionen

Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 Nur stabile Reaktionen

Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 alle Reaktionen

Komponenten SiO 2 - Al 2 O 3 - H 2 O Phasen KyaniteKy Al 2 SiO 5 SillimaniteSi Al 2 SiO 5 AndalusiteAnd Al 2 SiO 5  -QuartzaQz SiO 2  -QuartzbQz SiO 2 alle Reaktionen

Al 2 SiO 5

T ?

Gesucht: für 4000 Bar und Bar: ∆ a G(Sillimanit) = ∆ a G(Kyanit) ∆ a G(Sillimanit) - ∆ a G(Kyanit) = 0

678.5 o C

678.5 K

SillimanitKyanite V 0 [J/Bar] Sillimanit - Kyanite 0.581

SillimanitKyanite V 0 [J/Bar] Sillimanit - Kyanite = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J

≠

SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] Sillimanit - Kyanite = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J SillimanitKyanite Sillimanit - Kyanite

SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] Sillimanit - Kyanite = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J SillimanitKyanite Sillimanit - Kyanite

SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] Sillimanit - Kyanite = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J SillimanitKyanite Sillimanit - Kyanite

SillimanitKyanite ∆ f G [J/mol] 400 K 500 K 600 K 700 K 800 K 900 K 1000 K 1100 K V 0 [J/Bar] Sillimanit - Kyanite = 0.581·(3999) = 2324 J = 0.581·(9999) = 5810 J SillimanitKyanite Sillimanit - Kyanite K K

K ∆ r G(Sil-Ky) f 1 = a·x 1 + b f 2 = a·x 2 + b P = 4000 Bar

K ∆ r G(Sil-Ky) f 1 = a·x 1 + b f 2 = a·x 2 + b Nullpunkt (∆ r G = 0) : P = 4000 Bar

K ∆ r G(Sil-Ky) f 1 = a·x 1 + b a = (∂∆ r G/∂T) P = -∆ r S P = 4000 Bar ∆ r S = J/K·mol

K ∆ r G(Sil-Ky) f 1 = a·x 1 + b a = (∂∆ r G/∂T) P = -∆ r S P = 4000 Bar ∆ r S = J/K·mol

K ∆ r G(Sil-Ky) f 1 = a·x 1 + b f 2 = a·x 2 + b Nullpunkt (∆ r G = 0) : P = Bar

678.5 K K

678.5 K K

678.5 K K Kyanit Sillimanit